Roulette STAKING! Anyone knows?

Hi everyone,
[and with due respect to my Guru].

Today I wanna ask a question, by blabbering about,
how to MAXIMIZE profit in,
a given win ratio of bet spin taken.
Hope we could have lively discussion.
============
Say, suppose that in a 10 round of bet,
there will be 4 win [that a typical, below average expectation, say 40wins/100bet, 400/1000bet].
==============


Let me put in this way,
I have 6 BLACK marble, and 4 RED marble,
[Black=lose, RED= win].

I placed all the marbles, in a bag, then U will take out one by one, and CAST it aside, NOT returning the marble into the bag again, THUS u will win exactly four time, in any ten bet, in many permutation.

Since we know beforehand, that we will win 4 in 10 bet,
we can see that the best permutation win is, all RED in a row, for the 1st, 2nd,3rd and 4th attempt.
And the one of the bad= RED from 7th to 10th bet.

HOW U GOING TO MAXIMIZE THE PROFIT WITH ANY STAKING?
[Staking...not progression...
This mean , no matter win or lose , u go on, betting the predetermined 'progression"].

=============================
One of the popular staking is "Monte-Carlo" staking,
[thus bet 1,2,3,4,5,6,7,7,9,10...infinite]
no matter win or lose , u go on, betting to the right.

Lets see...
How much we may profit with the best and the bad win permutation.

BEST =FIRST FOUR ATTEMPTS= RED hits.

1st=bet 1
2nd=bet 2
3rd=bet 3
4th=bet 4
5th=stop, since we know only 4 win.

thus profit=+10.
=========
BAD=LAST FOUR=RED IN ROW


1st=bet 1=LOSE=-1
2nd=bet 2=LOSE=-3
3rd=bet 3=LOSE=-6
4th=bet 4=LOSE=-10
5th=BET 5=LOSE=-15
6th=bet 6=LOSE=-21
7th=bet 7=WIN=-14
8th=bet 8=WIN=-6
9th=bet 9=WIN=+3
10th=bet 10=WIN=+13 NET PROFIT.

=======
HOW TO WIN IN THIS PERMUTATION?

1st=bet 1=LOSE=-1
2nd=bet 2=LOSE=-3
3rd=bet 3==WIN=0
4th=bet 4=LOSE=-4
5th=BET 5==WIN=+1
6th=bet 6=LOSE=-5
7th=bet 7=WIN=+2
8th=bet 8=LOSE=-6
9th=bet 9=LOSE=-15
10th=bet 10=WIN=-5 NETT LOSS.


=======
WHAT IF WE LOSE ALL TEN, WHICH IS VERY POSSIBLE.

1st=bet 1=LOSE=-1
2nd=bet 2=LOSE=-3
3rd=bet 3=LOSE=-6
4th=bet 4=LOSE=-10
5th=BET 5=LOSE=-15
6th=bet 6=LOSE=-21
7th=bet 7=LOSE=-28
8th=bet 8=LOSE=-36
9th=bet 9=LOSE=-45
10th=bet 10=LOSE=-55 NET LOSS

THUS THE MILLION DOLLAR QUESTION=
HOW MANY "WINNING SET" TO OVERCOME LOSING
POSSIBILITY SET" ,
IN LONG RUN???

XXXXXXXXXXXXXXX
WHAT IF WE USE DREADED DANGEROUS MARTHY!!!

BEST FIRST FOUR ATTEMPTS= RED.

1st=bet 1
2nd=bet 2
3rd=bet 4
4th=bet 8
5th=stop, since we known, only 4 win.

thus profit=+15

=======
HOW TO WIN IN THIS PERMUTATION?

1st=bet 1=LOSE=-1
2nd=bet 2=LOSE=-3
3rd=bet 4==WIN=1
4th=bet 8=LOSE=-7
5th=BET 16==WIN=+9
6th=bet 32=LOSE=-23
7th=bet 64=WIN=+41
8th=bet 128=LOSE=-87
9th=bet 256=LOSE=-343
10th=bet 512=WIN=+169

=========
BAD=LAST FOUR=RED IN ROW


1st=bet 1=LOSE=-1
2nd=bet 2=LOSE=-3
3rd=bet 4=LOSE=-7
4th=bet 8=LOSE=-15
5th=BET 16=LOSE=-31
6th=bet 32=LOSE=-63
7th=bet 64=WIN=+1
8th=bet 128=WIN=+129
9th=bet 256=WIN=+385
10th=bet 512=WIN=+897 NET PROFIT.

=======

WORST=LOSE ALL!



1st=bet 1=LOSE=-1
2nd=bet 2=LOSE=-3
3rd=bet 4=LOSE=-7
4th=bet 8=LOSE=-15
5th=BET 16=LOSE=-31
6th=bet 32=LOSE=-63
7th=bet 64=LOSE=- 127
8th=bet 128=LOSE=-255
9th=bet 256=LOSE=-511
10th=bet 512=LOSE=-1023 NET LOSE

THUS THE MILLION DOLLAR QUESTION=
HOW MANY "WINNING SET" TO OVERCOME LOSING
POSSIBILITY SET" ,
IN LONG RUN???

XXXXXXXXXXXXXXX

NO!
THE above example is just EXAMPLE on how to play staking if we could predetermine how many set of attempt will win AROUND expectation, and lose ALL if the worst hit.
Of course if ONLY,we could sieved out the worst-set, we already had a GRAIL by winning more than losing set...in amount of profit/loss, of course.

The TRILLION question is,
the real question is....

Of course we cant predict random, and not sure of the outcome!

BUT,

If we are VERY sure that in FIVE attempt,we will win in 4 attempt, and lose 1 attempt, how are we going to STAKE?
Simply put, in 4 attempt. we win $X, and in losing attempt , we lose $Y, thus X must larger than Y.

How are we going to stake?
That is a grail.

xxxxxxxxxxxxxxxxxxxxx

 

Start from Bet 10, if the first bet loses, go with 20,40,80,160. If first one wins, go downwards, 5, 3, 2,1.

If we know or even can guess what can happen, it is always a win-win. If we know that there will be atleast one win in next 5 outcomes, we will use a martingale till first win and will not play thereafter.
My point is, we can't guess anything like that. so all these solutions will work in hypothetical cases only. Think of what can happen in real world.

 

No, not even then.

 

Literally get a bag, and your marbles, and go to work......let us know how it does....I am thinking it will come out horrible.