Roulette A twist/similar parachute (Turbo Genius)

A twist/similar parachute (Turbo Genius)
I attach hes parachute and write down the framework below.

You can pick any spread of numbers randomly with no selection and cover over twenty segments of bets with a fifty percent likelihood of winning for each segment.

The only downside is that it requires a very big bankroll and I can't think of any other way, then than you start with for example nineteen numbers spread for six attempts and then twelve numbers for four attempts.
Continue with six numbers for eight attempts and four numbers for twelve attempts.
Continue with three numbers for sixteen attempts and two numbers with twenty-four attempts.
Finish the whole parachute with fifty attempts with a single number.

Math and probability dictate you can lose your first visit or you need to play one million times before hitting such a sequence and the last number in the parachute can be your lucky number.
There is no other way in my opinion that would be more effective or closer to the truth than this solution.

If you know
To translate the chart:

EC one attempt
Doz two attempt
Line four attempt
Corner six attempt
Street eight attempt
Split twelve attempt
Single nr twenty-five attempt

You can use as many segments you want
and in any combination you want

Period
one feels free to share.

 

Nice. You can target a repeater or a waking sleeper. Slow and secure (enough). Thanks Sputnik.

 

I would suggest targeting the location that has appeared the least for the group you are on.
If there is a tie then wait out spins until you have one qualified by itself.
This is using that -


You could also target the location that hasn't shown the longest.
Either will work fine.

The way I did the above was "up and down"
1 unit even money for 2 spins
2 units doz/column for 3 spins
3 units line bet for 6 spins
4 units corner bet for 9 spins
5 units street bet for 12 spins
6 units split bet for 18 spins
7 units straight bet for 36 spins

Any win drops back 1 position in the list.
Any session can be over when the even money bet wins.
In the sample above the street bet location was reached and then all wins
after that brought it back to the even money win.
It is of course possible to work through the entire list and lose *disclaimer*

Cheers.
Turbo

 

Thanks Turbo, great to see you active again.
Shouldn't a street bet and a corner bet be the other way around though (switch places)? We are conventionally parachuting from the biggest partition to the smallest. Unless by corner you mean quad (a 9-number location) and the English nomenclature got in my way
+ After every win a new target group/compartment should be looked for based on appearance history.
Time for testing. Cheers,
MJ

 

Hello, I want to mention one thing about repeaters and sleepers using binomial probability.
The binomial probability shows the real weakness in your average selections.

Take one dozen that sleep 16 times and apply a 12-step progression, just one example for illustration purposes.
Then the dozen that sleep 16 times is equal to an 8 EC and the progression of 12 steps is equal to a 6 EC.
That is weak.

Cheers

 

Sorry, I got it now.

 

10 becomes 20
20 becomes 40
40 becomes 80
80 becomes 160
160 becomes 320
320 becomes 640

All that from a sleeping dozen.
Now add a zero to $10 and you start with $100

Or even better add some take off steps as you go so that you are guaranteed to get at least something as you progress to the final step, "Up & Pull."

Say three steps, take off from $30

You take off at step 3 $10 of the $30 so you take out $80. So no mater what happened you gain $50

Next you take off $10 more of the $30 at step 4, so you get $160 added to your already $80 for a total stepped Up & Pull of $240.

The last $10 goes all the way. So you get $640 & $240 for a total of $880 if it makes it.