Baccarat CHAT GPT / 88,04% win

When you record a pattern like BPBBBP, you can analyze the results and the probability of winning when betting according to a certain strategy like Martingale. Here is how to understand and analyze:

Analysis of BPBBBP pattern
B: Banker wins
P: Player wins
Results:
Banker (B) wins: 4 times
Player (P) wins: 2 times
Calculating the probability of winning in 6 consecutive games
If you apply the Martingale strategy for 6 consecutive games, you need to consider the following factors:

Probability of winning:

The Banker's probability of winning is about 50.68%.
The Player's probability of winning is about 49.32%.
The probability of a tie is about 9.5% (usually not included in Martingale bets).
Calculating the probability of winning at least one game: If you bet 6 consecutive games on the Banker, the probability of not winning in one game is 49.32%. So the probability of not winning in 6 hands is:

(0.4932)^6 \approx 0.1196 \text{ (about 11.96%)}
=> The probability of winning at least one hand in 6 hands is:

1 - 0.1196 \approx 0.8804 \text{ (about 88.04%)}
Conclusion
If you bet on Banker using the BPBBBP pattern and double down for 6 consecutive hands, the probability of you winning at least one hand will be about 88.04%. However, remember that doubling down is risky, especially if you are on a losing streak.

 

To calculate the probability of getting at least one bet correct in the P, B, B, B, P, B betting sequence, we will determine the winning probability for each bet and then calculate the probability of getting at least one bet correct.

Probability for each hand
Hand 1 (P):

Probability of winning: 49.32% (0.4932)
Probability of losing: 50.68% (0.5068)
Hand 2 (B):

Probability of winning: 50.68% (0.5068)
Probability of losing: 49.32% (0.4932)
Hand 3 (B):

Probability of winning: 50.68% (0.5068)
Probability of losing: 49.32% (0.4932)
Hand 4 (B):

Probability of winning: 50.68% (0.5068)
Probability of losing: 49.32% (0.4932)
Hand 5 (P):

Probability of winning: 49.32% (0.4932)
Probability lose: 50.68% (0.5068)
Hand 6 (B):

Probability of winning: 50.68% (0.5068)
Probability of losing: 49.32% (0.4932)
Probability of losing all 6 hands
To calculate the probability of losing all 6 hands, we multiply the probability of losing for each hand:

t all)=P(lost hand 1)×P(lost hand 2)×P(lost hand 3)×P(lost hand 4)×P(lost hand 5)×P(lost hand 6)
Calculate the probability of losing all
Hand 1 (P) loses: 50.68% (0.5068)
Hand 2 (B) loses: 49.32% (0.4932)
Hand 3 (B) loses: 49.32% (0.4932)
Hand 4 (B) loses: 49.32% (0.4932)
Hand 5 (P) loses: 50.68% (0.5068)
Hand 6 (B) loses: 49.32% (0.4932)
\approx 0.5068^3 \times 0.4932^3 \approx 0.1307 \times 0.0574 \approx 0.0075 \text{ (approx 0.75%)}
Probability of winning at least one hand
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Conclusion
The probability of you being correct at least one hand in the betting sequence P, B, B, B, P, B is approximately 99.25%. If you need more information or have other questions, let me know!

 

Without looking, it doesn't sound correct at all. Otherwise there would be a line of millions waiting for a seat to ATM this secret pattern lol.

 

Looks correct but you would still lose in the long run with a martingale. Ha.

I think with 50:50 you would be closer to 98.44% but two thirds of the pattern is Banker so it pushes the percentage higher.

 

88.04% win rate? Low 50s sustained is excellent.

 

No, 98.44% that you will win one out of the six decisions.

 

yes. The side board has 6 vertical columns. We only follow the first row. If 1 of the 6 hands appears, we wait for the next row.

 

marty could never work

 

-Chưa hiểu lắm là bạn đợi PBBBPB ra hay sao.Một cột đánh win 1 tay chờ 1 cột khác à hay ntn

 

this is best

 

HI vietnam74qt , what order we do to the chat GPT to get the winning ?

 

Interesting video, just trying to understand how to use it? So it's demonstrating that it's most likely you'll get 4 bankers per every 9 hands, right?

 

Yes, I do horizontal so it takes a while to setup. For this reason, I don't use this as often but it will work if you play towards 4 as indicated by the percentage. So you would only play the nineth hand. If there is already 6 bankers, you play the player. I usually wait for 3-4 misses before making my bet.

 

Ignore what's written behind because it's another strategy. Look at the green markup Strategy takes a bit of time but works quite well.

 

Another sample

 

Probabilty of Banker does not change based on the previous results.

 

The probability of the banker win is 0.4932 and not 0.4586 in the DeepSeek program.

 

You cannot base your play off of probability. If you do that, then you'll always be betting on banker. Give that strategy a shot and see how it goes for you. Didn't work for me.

 

To determine the probability of having **at least 4 Banker wins** in **9 hands** of Baccarat using an **8-deck shoe**, follow these steps:

## **Final Answer:**
The probability of having **at least 4 Banker wins in 9 hands** is approximately **75.3%**.
*(This calculation assumes no ties. If ties are included, the probability would be slightly lower, but the difference is negligible for practical purposes.)


Then.....

To determine the probability of **at least one Banker win in the next 3 hands**, given that in the last **6 hands**, only **2 were Banker wins**, we can proceed as follows:

### **4. Final Answer**
The probability of **at least one Banker win in the next 3 hands** is approximately **88.0%**.