Roulette A Fascinating Pattern You Might Have Overlooked

Hey everyone,

I am new to this forum but I am not new to gambling. I have been playing roulette and baccarat for over 16 years now and I recently found something interesting that I will like to share with everyone. Now first and foremost, I am not saying this is a winning strategy or it's an holy grail. But I found it interesting.

Please keep an open mind—this isn't something you can simply program into RX software and test over 1,000 spins to determine its effectiveness.

After playing for 16 years, I stumbled upon some really interesting concept that I hadn’t seen much about elsewhere. There is an anomaly that occurs once every 46 spin cycles. Now of course this can happen back to back but overall, from my time playing this way I learned that on average it only happens once or twice every hour on a live dealer.


I spent some time breaking things down in a way that’s easy to follow and, hopefully, makes it a bit more digestible.

Onto the strategy:

We want to wait for a rare combination of numbers that are complete opposite to each other to land.
Once this occurs, we wait for a unique pairing and once it occurs, we bet on that 1 thing these
set of numbers have in common. In my experience, you will win within the 1st-4th bets. The only time
it doesn't win immediately is because the anomaly occurs again back to back or an streak of the opposite of the outside bet starts for ins (which technically is an anomaly itself).

The Setup:

#18 <----- Red, Low, Even ........ There is only one thing in Common in these results, it's EVEN
#22 <----- Black, High, Even,
#5 <----- Red, Low, Odd


So our next bet would be EVEN:

Result: #26 lands and we win!

This strategy isn't sexy and it's time consuming but I have gotten good results trying. I have attached some PDF files to demonstrate the strategy. Looking forward to some insights from other experienced players.

Happy learning!

 

So when we have 2 of the same EC in a row and then a change....we bet the penultimate to happen.


examples:

RRB bet R
OOE bet O
LLH bet L

Right?

 

Interesting thxs, I play outside bets looking for symmetrical patterns then bet against them, all symmetrical patterns have to end eventually.

 

Can you afford eventually

 

You do not know WHEN....so it has no value

 

You are wrong

 

Eventually isn't too far away

 

Thank you for your response mate, the answer is no because your over looking the key component.

Okay so the set up is a combination of 2 numbers being completely opposite to each other.

For example this the set up:

Red, Low, Even then a Black, High, Odd.

If the next number that lands is Red, Low, Odd

Then we will place a bet on Odd but it must be in this particular order.

The reason being is because if you simplified to only 1 category then it's not an anomaly because Even, Odd, Odd occurs all the time.


These are unique pairings of numbers that doesn't happen very often, now in order to make a bet the third result must only have 1 thing in common with the 2nd result.

I know it might be somewhat complicated, I have a video explaining it but unfortunately, I can post any links.

 

Appreciate you for being open minded, I look forward to seeing if you tried it out and see if it worked. Even if you only win 1 unit, I did my part.

 

I've been doing it for the past 72 yrs now, sorry I haven't taken a screen shot of all the wins

 

Are you using progression?

 

I wasn't trying to offend you buddy. Just showing you appreciation for being open minded.

 

Which ever one suits you and your bankroll best

 

Never thought you was bro

like I say I’ve been doing this for years now, just haven’t taken screenshots of all the wins sorry.

 

I wanted to test the effectiveness of this pattern by programming it with real archive numbers.
The source is WestSpiel Casino , Year 2007, Table 7.
That's 350 days or 93449 spins.

In all, there were 3893 attempts.

total spins to win = total occurrences
-----------------------------------------
1 = 1897
2 = 1025
3 = 483
4 = 219
5 = 125
6 = 67
7 = 36
8 = 13
9 = 10
10 = 8
11 = 5
12 = 3
13 = 1
15 = 1

This looks like a standard distribution. I don't see any advantages.




For example, the first day starts like this:

(2007-january-01)

1. (6) BLE
2. (27) RHO
3. (28) BHE ------ bet High
4. (1) RLO ---------------------------- bet Odd
5. (33) BHO ------ win at 2nd ------- win at 1st
6. (35) BHO
7. (32) RHE
8. (12) RLE
9. (7) RLO
10. (30) RHE
11. (25) RHO
12. (2) BLE
13. (34) RHE ------ bet Even
14. (35) BHO
15. (2) BLE ---------win at 2nd
16. (13) BLO
17. (17) BLO
18. (0) GGG
19. (10) BLE
20. (35) BHO
21. (29) BHO
22. (15) BLO
23. (20) BHE
24. (11) BLO
25. (16) RLE
26. (18) RLE
27. (12) RLE
28. (23) RHO
29. (26) BHE
30. (9) RLO
31. (1) RLO
32. (23) RHO
33. (15) BLO
34. (2) BLE
35. (22) BHE
36. (0) GGG
37. (28) BHE
38. (24) BHE
39. (24) BHE
40. (9) RLO
41. (33) BHO -------- bet Odd
42. (28) BHE
43. (15) BLO -------- win at 2nd
44. (34) RHE
45. (32) RHE
46. (6) BLE
47. (2) BLE
48. (36) RHE
49. (4) BLE
50. (17) BLO
51. (22) BHE
52. (14) RLE
53. (23) RHO
54. (16) RLE
55. (12) RLE
56. (18) RLE
57. (18) RLE
58. (10) BLE
59. (14) RLE
60. (34) RHE
61. (34) RHE
62. (30) RHE
63. (27) RHO
64. (29) BHO
65. (3) RLO
66. (17) BLO
67. (20) BHE
68. (30) RHE
69. (25) RHO
70. (34) RHE
71. (31) BHO
72. (3) RLO
73. (20) BHE
74. (10) BLE
75. (13) BLO
76. (6) BLE
77. (34) RHE
78. (1) RLO
79. (24) BHE
80. (27) RHO ------- bet High
81. (8) BLE
82. (16) RLE
83. (6) BLE
84. (15) BLO
85. (21) RHO -------- win at 5th
86. (17) BLO
87. (31) BHO
88. (11) BLO
89. (21) RHO
90. (3) RLO

 

As stated, you usually win within the first 4 spins. The only time it doesn't is when the anomaly occurs back to back or another streak of the opposite occurs (which is an anomaly in itself)

 

This is always true of any bet selection in a near 50:50 game.

If it was a true 50:50 game (it's not)...

1st spin: 50% wins
2nd spin: 25% wins
3rd spin: 12.5% wins
4th spin: 6.25% wins

So 93.75% of your wins would be within 4 spins. It is always the outlier beyond 4 spins that wipes you out when using a progression.

 

@Calculatedrisktakers here's image of a system-performance
look at the violet columns, till (-5) about ≈90% of the games are resolved in positive
then take notice of the increase in units for each extra single-%
how much extra is required to secure extra how much more bankroll is required +99% efficiency comparably .. that's where it only begins relevant to roulette
& mind, there's no negative progression here, this is played flat!

 

Is this a short term?

For you -5 = 90% sounds like you are implying a 10% risk of ruin (ROR), to boost efficiency from 90% to 99%, the goal is to reduce ROR from 10% to 1%. This requires a larger bankroll to absorb variance.

90% ->95%: 2x bankroll
95% ->99%: 4x bankroll

To achieve 99% efficiency, the bankroll might need to be 5–10x larger than the stop-loss threshold (e.g., 25–50 units for a -5 stop-loss), depending on bet frequency and size

 

Relatively, yes. 322-games only. About 5% of thise finish on the first-spin.
Or 5x-sessios to about +50 units.
The exposition:game (-units:spins, U:L) parameter for the games within each session are in the bottom-right squares, only the games worse than (-5) are registered.

You may have to open the image in a new-tab for better clarity.

Yeah, 99% ror would be only the begining of the proper-work, ideally you want to get very close to 100% ... 99.75% (1 in 400 games) if using multiple reserve-bankrolls.

& extending that play further you might realize that the bankroll-increase-rate to secure each additional 0.1% after reaching 99&% (& each 0.01% after reaching 99.9% as well) .. is pretty much the same as 90-99%, just continuing further ..

So if it took 4x the (-5) amount or (-20) to reach 99%, you are looking at 8x or (-40) for 99.5% .. & somewhere about 60-80u for the 99.75%.

Without using neg.prog. ofc!