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Roulette The horse race analogy and set completion

Discussion in 'Roulette Forum' started by TurboGenius, Oct 18, 2019.

  1. jekhb1976

    jekhb1976 Well-Known Member

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    So now we understand this, the next question is, how do you always end up in profit! each and every session.
     
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  2. Bitrock06

    Bitrock06 Active Member

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    Jekhb, as soon as a set qualifies and I begin to bet on it I begin a whole new list of sets and cross off numbers. There seems to be a pattern going on in there as well..

    So as soon as for example "set 3" has one number on it, I bet all of set 3s numbers and create new sets and a whole new race.
     
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  3. daveylibra

    daveylibra Member

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    Bitrock, I agree that we begin a new list of sets after we have a qualifyer, but surely we bet only the one number? If we bet the whole set, that is more than 1-4 numbers.
    BUT, imagine 100 or more people creating random sets on the same wheel. Then some unfortunate players will always be on the coldest numbers, and so cannot win?
    Over to Turbo!
     
  4. Smitridel

    Smitridel Active Member

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    At first this was my interpretation as well.

    But as Ive posted above I had 2 numbers from two different sets that were chewing my BR downwards and they were proven both sleepers and the 1st f them was for 40 spins (much below than payout ratio).
    Unless you use negative progression (1-5-25) there is always the risk that 1 or 2 qualifiers will be sleeping for more than 37 spins.
    But sometimes they come before.
    Sometimes they dont.

    I posted a graph of a 2 sleeper number using lines groups (example) and I had the encountered the same problem on the other thread.
    If you're not going to use negative progression you'll always be in the risk of sleeping numbers.
     
  5. Benas

    Benas Active Member

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    You are maybe right in understanding what turbo explained, but that you understand that right, not prove that turbo is right!

    That will be more clear think this say are a group of numbers in which fallen all, but one - no - your horse is in the total first place and you bet on it - that number which is left? So your group was 1-2-3-4 fall 1-2-3 you bet on 4 - right?

    But now think that are 33 other players and they play accordingly the same system only they choose groups differently !! 123-5 123-6 123-36 and so on.

    What we will have - all play the same system, but all do different bets :) !!!
     
    Last edited: Oct 20, 2019
  6. Bitrock06

    Bitrock06 Active Member

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    My sets are 4 numbers. I'm only betting 4 numbers.
     
  7. Bitrock06

    Bitrock06 Active Member

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    I don't know shit. So what I say must be taken with a grain of salt haha.

    However, from what I understand, once a set is "in first place" we bet on those numbers and in the meantime we have new sets with numbers getting picked off one by one. We are not worried about second or 3rd place. Turbo said this as ka2 was trying to pick things apart.
     
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  8. Smitridel

    Smitridel Active Member

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    Something to point out: After you picked your #5 from the first set, do you see how many numbers from the leading set are appearing?
    Just look at the next 20 spins after you picked 5.
    What do you see?
    Do you see "Set 1" as a set being repeated?

    And also since I dont know what spins were before, in the leading set (Set 1) what was the hottest number up to that point? Or the second hottest? ;)
     
    Last edited: Oct 20, 2019
  9. Smitridel

    Smitridel Active Member

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    I think 4 numbers is small.
    I would suggest you use something larger.

    I agree I also bet (in the above tests) the set as a whole and not a specific number from that.
    Now to narrow it down...Thats what Im searching.
     
    Last edited: Oct 20, 2019
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  10. Bitrock06

    Bitrock06 Active Member

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    I am betting the set as a whole. 4 numbers. And I am testing other sets, but I noticed a pattern going on as I'm betting and building my next race. Have you noticed it?
     
  11. Bitrock06

    Bitrock06 Active Member

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    With you on the "narrow it down" part bro!
     
  12. stringbeanpc

    stringbeanpc Member

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    jekhb1976, I do not understand how you get that set 3 won first place ?

    using your supplied sets and spins I see to start betting on Number 29 after Number 34 appears on spin 21.
    Therefore betting only on Number 29 in set 4, because all of the other sets have numbers remaining
    Set 1 has 3,8,9 remaining
    Set 2 has 10,11,12,16 remaining
    Set 3 has 21,24,26 remaining example.jpg
     
    Last edited: Oct 20, 2019
  13. jekhb1976

    jekhb1976 Well-Known Member

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    it started here...

    SET 1: (01) (02) (03) (04) 05 (06) (07) (08) (09)
    SET 2: (10) 11 (12) (13) (14) (15) (16) (17) 18
    SET 3: (19) (20) (21) (22) (23) (24) (25) (26) 27
    SET 4: (28) 29 (30) (31) (32) (33) 34 (35) (36)

    1 31 35
    30 30 26
    8 30 4 set 2 has last # left #5 (so we bet #5, wich is the last # in this set (Sleeping number)
    1 31
    16 8 0 (-1)
    36 21 10 (-2)
    0 22 20 (-3)
    13 6 24 (-4)
    6 36 15 (-5)
    1 19 15 (-6)
    12 36 15 (-7)
    28 25 31 (-8)
    12 36 14 (-9)
    16 33 32 (-10)
    2 13 25 (-11)
    9 28 17 (-12)
    21 13 7 (-13)
    12 0 31 (-14)
    3 6 3 (-15)
    31 28 14 (-16)
    25 7 23 (-17) set 3 has also one # left (so we bet #27 wich is the last in this set (wich is still a sleeping #)
    36 5
    32 32 27 win! set 3 has won the race.

    Profit : +17
    drwdwn : -17
    total spins played : 67
     
  14. jekhb1976

    jekhb1976 Well-Known Member

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    Maybe a crazy thought, but this just came to mind.

    What if we play it different?

    We have 6 sets of 6 numbers for example.
    Instead of waiting until one of these sets have one number left to be hit (wich in my mind is still a sleeper) we play this around the total of hits a line has had.

    So we track our lines until one of the lines has had 5 hits. Our finish line is 6 hits.

    So we start to bet on that line, wich is the closest to the finish. and we also bet 1 unit for example on every number that has hit in this line. (This way, we aren't betting on any sleeping numbers).

    Again, just a thought. A little different look at things if you will.
     

    Attached Files:


  15. Smitridel

    Smitridel Active Member

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    Thats what I pointed you before lol ("Look at the 20 Numbers after")
    Good to know you caught it even if you havent read my post lol

    Now time to narrow it down. Less investment in numbers oglf the leading line =more profit
     
  16. stringbeanpc

    stringbeanpc Member

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    jekhb1976, good way to catch repeaters and try to break even when a sleeper hits.
    What if we also bet on the Line the same amount as the total of the straight up bets.

    Example. You are betting Line 19-24, of which 19 hit once, 20 hit once, 23 hit twice and 24 hit once. Therefore 5 total hits.
    Play one chip each on 19,20,23,24 and 4 chips on Line 19-24.
     
  17. Smitridel

    Smitridel Active Member

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    You mean 5 units on hit numbers and 1 in line?
    Thats the same thing if you bet on the sleeping as well only with the exception that if you hit aby else you get the line profit as well.
    But if you hit the sleeping?

    Thats why I say bet all 6.
    Either way you get the sleeping more times than not.
     
    Last edited: Oct 20, 2019
  18. daveylibra

    daveylibra Member

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    Wait a minute guys!
    Turbo said he bets 1-4 numbers max, right?
    His sets were more than 4 numbers. In the lines example, 6. In the random example, 7.
    So he is not betting the whole set!
    Its fine to divert from his method if you want, but I thought we were testing/working out his method because he
    claims its a winner?
     
  19. Smitridel

    Smitridel Active Member

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    Exactly.
    I've done tests with success using the whole set as bet (each number on the set).
    However I've also underlined the need for narrowing down our options.
    An idea that Im exploring right now is watch the performance on the other numbers in the "winning" set.

    So for example lets say that Set 1-6 quallified, it has hit 5 numbers and it has one left and is already ahead of any other set.
    I check the "performance" of numbers that already hit throughout the spins and bet accordingly.
    This is done because "naturally" the set IS performing above average as a whole.

    So If I see at least 1 above average number inside that has already hit 3 or 4 times, I will pick that.
    4/6 tests as of yet, have succesfull results.



    P.S. I wonder though if there is another way by studying the performance of each number in relation to what stage of the spins we are.
    So If we have a number inside the set that is only R2 (Repeated 2 times) and we're at 111 it's "due" to happen at least once trying to get closer to R3 and R4.
     
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  20. Naughty but nice

    Naughty but nice Well-Known Member

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    upload_2019-10-20_19-20-33.png

    The 1st contender is #10 after 16 spins! It's still running.

    A 2nd contender entered at spin 22, #2. This contender wins

    Betting the 2 contenders is 24 units and profit! But 1st contender is slow.

    The winning contender is a contender again.



    Bet every spin as in the riddle; but use only the 4 hottest!

    Using; slow progression a profit.

    upload_2019-10-20_19-21-29.png
     

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