Roulette Easy EC 2

It should be hard flatbetting any EC and win, but we'll see about this betselection. It could just be beginners luck from the first test, or else i have found something here?

The logic with this system, is that I consider a repeating group of nine (RED LOW, RED HIGH, BLACK LOW, BLACK HIGH) to be a RARE event. Therefore i bet against a repeating group of 9, (whenever they happen) with 2 EC's: BLACK/RED & HIGH/LOW

So, for an example RED LOW hit two times in a row, -Now the bet will be BLACK & HIGH. The only chance it will lose, is if zero hits, or a THIRD REPEAT happens and so on...

Another example BLACK HIGH hit two times in a row, -Now the bet will be RED & LOW.

STOP, and retrack (wait for a new group of nine to repeat) after each hit or doublehit.

If zero hits, STOP

a mild progression is used, for each loss (for each repeat beyond 2 repeats) +1u bet. Reset to 1u after a hit or a doublehit.

First test was played with 25u bets

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