Roulette MARQUEES' '3time repeat of a number'

Hi Everyone,
and due respect to my Guru.
========================


This is not my ideas, but a

professional gambler's idea...

But he didnt show the progression method...

I try to combine with Vaddi

progression, or sort of...
=============

It never fail to amazed me

every time I in a casino,


'3time repeat of a number'


always show up on the

Roulette Marquees! Some

time up to 3 or 4 unique

numbers...[on a 20 to

30numbers marquees]
===========

The method, I think we could

win with..

1] Bet when the "number

that had repeat twice" [show up twice] on the marquees,

hoping for 3rd repeat...bet

till the number out of the

marquees, [ become a

single...to stop betting

that number]. And wait for a NEW twice repeat to

resume bet.
If there are 2 or 3 unique number appear as TWICE repeat, then u adjust the bet accordingly...
====================

The progression=1,2,3,3...

====================
this an EC bet example so u get the idea...

bet 1, lose...
u bet 2, lose again,
u bet 3, lose again,
now u bet 3 AGAIN...lose..
and bet 3..lose again..


u recorded them from left to right as ...

1,2,3,3,3

u need to bet 3 as long as there still 1 & 2 on the paper.

Bet 3=win, now u strike off the 1 and 2...and will look as

3,3,3

bet 4 as there no more 1&2...

Bet 4=lose, so will like as

3,3,3,4...
bet 4 as there still 3,3,3

bet 4=win...will be...

3,3,4...

bet 4=win...will be...

3,4...

bet 4=win...will be...

4...

bet 5=win...

====================
For the straight number, to bet the number will repeat for the THIRD time....

1] Bet 1u, for say, 30time.
If fail to hit after

30time, bet 2u for 30 time,

if fail again, bet 3u for

30time, if fail again, bet

3u AGAIN, for 30 time till

hit!

Thus u recorded them as,
1111111111
1111111111
1111111111[30x]=30u losses
2222222222
2222222222
2222222222[30x]=90u losses
3333333333
3333333333
3333333333[30x]=180u losses
3333333333
3333333333
3333333333[30x]=270u losses

3333333333
3333333333
3333333333[30x]=360 losses

the above example, to show

that if u have fail to hit

after 150 attempt!

Say if u hit after 150th

attempt,[where u still bet

3 unit], U cross out the 1

and 2 that u recorded...

and what left, will look loke below...

3333333333
3333333333
3333333333

3333333333
3333333333
3333333333

3333333333
3333333333
3333333333

now u will bet 5u...
if u hit somewhere before 30 attempt

u strike off the first 3,
and will look like below

3333333333
3333333333
3333333333

3333333333
3333333333
3333333333

u still bet 5u, if hit again, u still bet 5u,
if hit, then u strike off the 3, with last set of 3 standing...will look like below..

3333333333
3333333333
3333333333

u need to hit one more time to produce profit, if fail after 30 attempts, then...will look like below

3333333333
3333333333
3333333333
5555555555
5555555555
5555555555

thus need to bet 6u for 30attempts...

What u think?

 

This is what I think: not long from now you will lose a lot of money.

 

If I know it will be Three numbers in a row every evning at the casino, I would bet one unit straight up, follow the last number, and then parlay the winning from the second hit. With a 5 Euro bet it would gain over 6000 every night.

 

@Jesper Svensson ,
it is not three numbers in a row but a number showing a total of three times in the marquee. I think BTW refers to this: http://albalaha.lefora.com/topic/42...-Defeat-RouletteUltimate-Edition#.VSYvU9yUcr0

 

Three the same on the 21 number marque at BV is almost allways. And then probably to late to gain. The next show has 1/37 chanse. History tells nothing. We know however it will be repeting numbers most of the time, or near allways.

 

History tells you to learn from your mistakes. If you think mathematically, nothing can ever help you win in gambling so better quit gambling than talking of it.