Roulette Parachute method

7 to 5

Monday through Friday.

 

Casino (B&M) is 3-6 days a week, depending on such-n-such.

Work?? (lol) Part time.

Ken

 

My day job is to move a few sprinklers.

 

My sister always has to stop at Sobelmans every time she goes there.

 

They just had $1,500 stolen from there yesterday.

Ken

 

or Saturday >> https://www.jsonline.com/story/news...sobelmans-saturday-night-hit-thief/920651002/

 

My parachute method here only loses with greed

Wins well hit and run

I’ll add it to my ammo box

 

Last time we were there in the winter, myself my sister and her husband we had three Bloody Mary's and three shots and one sandwich we split and the bill was over $200.00, yes $200!! . The Bloody Mary's were only about $50 each , no words to describe it LOL!!

 

Parachute system
lmfao

 

The title was in an effort to troll member falkor

It’s the hit and run that matters

 

Although its appreciated you posted something, you'll see as the years go by, it is NO LONGER worth it.

IT IS NOT WORTH IT. More headaches than you really need.

Besides, you can easily test (etc.) without the approval of others. Thats why I posted so much stuff back in the day. I was looking for approval, "Great job Ken, you rock"!!!!

F**k all that noise, its not necessary as I have learned. Having HUNDREDS in your pocket is far more important compared to the viewpoints of others you will never even meet (lol)

Ken

 

Nope. Not worth it

And the wizard of Vegas forum boys don’t fool me

They to, are there for a reason. Browsing the boards.

 

You might think it's working with Hit&Run simply because you're comparing on one side A a sample of few spins and on another side B a sample for example of 100 spins. The thing is when you'll play 100 spins of Hit&Run you might get same result as the side B upper.

It will just take the time to go 100 spins, some will do it in 2 weeks/1month/6 months and of course during that time we'll believe we're clever than others...

 

RG a selection process for a Parachute method using hit and run.
This is how I did and maybe it can inspire you.

I took a Parachute method that has 100 attempts.
Then I look at the binomial probability for one single number to hit with 50% probability.
That is within 25 attempts.

Then I use the single numbers hit or no hit as selection process using a known pattern.
Even if the 100 attempts for the single number fail around 16 times during 100 sessions, so do they still win using the Parachute method.
Both Parachute method and final target number have to fail in the same moment.
The single number or target number is there for the majority of times, so when the parachute method fail also the target number has to fail.
That is two random elements and each one hold its own probability of likelihood to happen.

If you can implement such selection into your parachute method you will operate with casino money after a short period of play.

Cheers

 

So for example

Use my parachute method

If it fails start on a single number?

 

No, you missunderstand.

 

@Sputnik

Could you show an example? or it was just to drop an idea maybe?

 

Ok, every time you get 50 versus 50 the final target number does not show during 100 attempts, one single number.
Each time you get below 50 the final number, one single number show within 100 attempts.
So the parachute method has the fail when you get 50 versus 50 attempts where the single number not show.
This means that out of 53 sessions I only risk my money 5 times.
So when the single number does not show within 100 attempts I also need to lose Nine EC bets in a row during the same momentum if the Parachute method should bust.
The parachute method play against Nine to Ten EC bets using binomial probability calculation.

Code:

1. 21 +1
2. 7 +1
3. 34 +1
4. 30 +1
5. 7 +1
6. 26 +1
7. 36 +1
8. 32 +1
9. 18 +1
10. 6 +1
11. 6 +1
12. 34 +1
13. 49 +1
14. 43 +1
15. 13 +1
16. 8 +1
17. 11 +1
18. 42 +1
19. 6 +1
20. 50/8 +1
21. 33 +1
22. 5 +1
23. 34 +1
24. 7 +1
25. 14 +1
26. 4 +1
27. 18 +1
28. 24 +1
29. 37 +1
30. 33 +1
31. 36 +1
32. 50/21 +1
33. 50/18 +1
34. 50/50  +1 single number fail but parachute win
35. 34 +1
36. 50/50  +1 single number fail but parachute win
37. 50/6 +1
38. 3 +1
39. 50/50  +1 single number fail but parachute win
40. 1 +1
41. 9 +1
42. 9 +1
43. 3 +1
44. 35 +1
45. 50/50  +1 single number fail but parachute win
46. 40 +1
47. 50/48 +1
48. 50/15 +1
49. 37 +1
50. 21 +1
51. 50/36 +1
52. 50/50 +1 single number fail but parachute win
53. 50/17 +1

 

Thanks for the detailed example, i'm going to read that twice.