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Roulette The Turbo Thread

Discussion in 'Roulette Forum' started by trellw24, Feb 2, 2019.

  1. jekhb1976

    jekhb1976 Well-Known Member

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    funny
     
  2. trellw24

    trellw24 Member

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    It just seems like betting too many numbers gives you too much of a drawdown even when you do get a hit to give enough profit most of the time. What do you think about this ?
     
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  3. mr j

    mr j Well-Known Member

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    I do want to chime in. I agree with this statement with no ill regards towards any persons method, Turbo or otherwise.

    Ken
     
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  4. jekhb1976

    jekhb1976 Well-Known Member

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    true.
     
  5. jekhb1976

    jekhb1976 Well-Known Member

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    what about, we wait 12 spins, and look how many repeats there are out at this point. usualy no more then 3. so you can expect in the next 24 spins aprox 7-9 repeaters still underway. every spin we play a random unique number, up to max 12.
     
    stringbeanpc likes this.
  6. BETJACK

    BETJACK Active Member

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  7. Nathan Detroit

    Nathan Detroit Well-Known Member Founding Member

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    +Clowns make the best double agents in the Intelligence community .



    ND
     
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  8. mr j

    mr j Well-Known Member

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    Not the waiting thing please but it is Turbo's thread.

    Ken
     
  9. trellw24

    trellw24 Member

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    I think the main point I'm trying to make is, if we know a number appeared it is a potential repeater. This is a fact, and is helpful but what I'm asking is, is there a second filter we should be applying because it seems too many numbers appear THEN don't show up enough to justify betting on them in the first place. It is true you cant lose a single unit by not betting on a number that doesn't show but what about a number that appears once then goes to sleep? This is where I think a Turbo analogy would do some good lol
     
  10. TurboGenius

    TurboGenius Well-Known Member Founding Member

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    You could look at it longer term.
    For example - when the last number appears (using straight ups for example)
    what have the other numbers done to make up for all these spins with the absence of the last
    number ? (the math has to stay correct and it does).

    Example 1 = 151 spins, last number shows (#20)
    #17 and #2 appeared 8 times. (+1.97 std deviation)
    18 different numbers on the table flat bet would have produced a profit,
    they all appeared above what's required to beat the house edge. (almost 1/2 of the table)

    Example 2 = 156 spins, last number shows (#2)
    #4 appeared 11 times (!!).
    16 different numbers on the table flat bet would have produced a profit

    Example 3 = 112 spins, last number shows (#18)
    #2 appeared 9 times (!!). (3.48 std deviation)
    14 different numbers on the table flat bet would have produced a profit.

    Example 4 = 196 spins, last number shows (#34)
    #2, #5, #21, #23 appeared 9 times). (1.63 std deviation)
    15 different numbers flat bet would have produced a profit.

    You can test this yourself, it always happens. X happens, so Y has to happen.
    You can't have a number going 150 spins without appearing and not have
    numbers appearing 8,9,11 times. Well above what's needed.

    As a matter of fact - betting any one of the 18 numbers from example 1,
    16 numbers from example 2, 14 numbers from example 3, 15 numbers from
    example 4 flat betting would have ended in profit.
    No one should expect you to be able to have picked the #17 or #2 in ex 1,
    or the #4 in ex 2, or the #2 in ex 3, or the #2,5,21 or 23 from ex 4.
    There's no time machine and no prediction can be 100% - but each and
    every spin we have data to work with - more of the puzzle is revealed.
    What numbers will more than likely produce what results, etc.
     
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  11. 6th-sense

    6th-sense Active Member

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    A number repeating also won’t carry on forever in its original position..say it came out on an even spin..it’ll eventually come out on an odd spin and vice versa..just an idea for you
     
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  12. stringbeanpc

    stringbeanpc Member

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    Just my thoughts, could be right or wrong.

    This chart shows what would happen if you bet each number immediately after it repeats and increased bet amount by 1 unit after each win
    using three scenarios
    1) Bet until the End of Cycle - Lose 42 units
    2) Bet for 18 spins - Lose 17 Units
    3) Bet for 13 spins - Profit 5 Units

    Turbo says in post 11
    I had wins on #21 but missed the wins on #35 - that's how it works with predicting.
    Like I said in other posts, I can't get all of the top performers and don't need to.
    I'm usually on the 7 or 8 of the top 10 appearing numbers over time so it works out fine.

    Number 21 wins 4 times, on spins 15 16 29 30
    Number 35 wins 3 times, on spins 04 33 36

    Remember the video Turbo posted about random
    https://www.gamblingforums.com/threads/repost-of-1961-video-for-those-who-asked-for-it.12241/

    I think the reason Turbo caught #21 but missed #35 has something to do with
    the "half life" described near the end of the video using dice

    I also think how many spins have occurred between the number repeated and calculating an average
    as Turbo showed in first post of this thread https://www.gamblingforums.com/threads/more-on-that-so-called-fallacy.11984/

    This average MAY be an indication if a number is growing hotter or colder ??

    A filter could be that this "average" should be less than or equal to whatever value turbo has selected as the "half life"

    That is all for now, and thanks to turbo for the info in post 50.

    Turbo, am I on the right track ?

    p.s. I was working on this while the trolls did their gong show above
     

    Attached Files:

  13. BETJACK

    BETJACK Active Member

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    93bb211111357124.jpg

    13 numbers in profit ...
    we can expect from 1/2 to 1/3 of all numbers to make a profit.
    in each cycle of 36 spins.
     
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  14. trellw24

    trellw24 Member

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    I see what you mean, but are the numbers that are under performing giving you hints as to what numbers might be above std deviation during your play besides that they have appeared?
     

  15. BETJACK

    BETJACK Active Member

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    b4d3401111380754.jpg

    my attempt to repeat the game
    Something is not right.
    number of numbers
    or
    progression
    or
    both.
     
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  16. TurboGenius

    TurboGenius Well-Known Member Founding Member

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    Sure. The math always stays the same.
    So 12 numbers not appearing (for example) in a cycle means other numbers (that have already appeared)
    will repeat. Which ones ? Well.... in my example..

     
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  17. trellw24

    trellw24 Member

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    How many numbers were you betting?
     
  18. trellw24

    trellw24 Member

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    Ok so let's say I choose 5 numbers that have appeared in the first 38 cycle and I have a really bad run and only hit once, now I'm in the negative, do I keep playing more cycles and switch the numbers I'm playing with the information I have, Or do I just hope that the numbers I originally chose will start to make a comeback down the road.
     
    jekhb1976 likes this.
  19. eugene

    eugene Well-Known Member

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    Exactly! I forget who said that there is a war on for people's mind, never mind their wallet!
    N.D....At least you didn't come down the Clyde River on a Banana Boat! (an old saying)
     
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  20. jekhb1976

    jekhb1976 Well-Known Member

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    play a few cycles on rx. look at cycle 1 and wich numbers only hit once. now follow them up to the next couple of cycles, what do you always see happening?
    they will catch up with the other numbers.
     
    Last edited: Feb 2, 2019
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