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Roulette The winning ratio

Discussion in 'Roulette Forum' started by BlueAngel, Dec 15, 2021.

  1. BlueAngel

    BlueAngel Active Member

    Joined:
    Aug 27, 2016
    Likes:
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    nowhere
    This is straight up numbers flat betting, but could be utilized with progression as well.

    We are betting every number which comes, thus we are adding up to the total betting one number per time.
    Let's say we lose for 10 spins in a row, therefore:

    -1, -2, -3, -4, -5, -6, -7, -8, -9, -10, a total of 55 units draw-down, on the 11th bet we are winning and the new total becomes -30.
    Every time we are winning we will remove 2 numbers, the winning one and the last (most recent), if the winning one was the last spun number then remove the before last as well.

    So now we would bet 9 numbers and lose, 10 numbers and lose, 11 lost, 12 numbers and win this time, thus the balance stands on: 30+9+10+11= -60 units minus 24 from the last win equals 36 units down.
    Let's assume that there were another 5 losses in a row: -10, -11, -12, -13, -14 thus now we are down by 96 units with 2 wins VS 18 losses and we would bet 15 numbers for the next spin.

    We win 21 units and the balance becomes -75, we would remove the winning and the last number (or before last), thus 13 numbers bet for the next spin.
    Let's say we would win this too, further reduction for the negative balance which now stands at 75-23= minus 52 units after 4 wins and 18 losses.

    The next 5 spins provide 3 wins and 2 losses and i would occur like this:
    -11, +24, +26, -8, +27 for a total of: (24+26+27)-(11+8)= 77-19= 58 deduct the previous 52 units drawdown and we would have gained 6 units net for 7 wins VS 20 losses out of 27 spins/bets.

    Just remember:
    Add 1 and remove 2!!


    Do you have any questions?
    Please leave your comments below, thank you.
     

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