Roulette 4,4,3,2,1,1 (6 lines in 15 spins)

Just to recap and as I mentioned in Turbo's Forum the other day, the numbers in the header are the breakdown for what will happen on average in a 15 spin sequence with the lines.

Thinking about that and my attention turned to the E.C's. There is nothing stopping anybody playing 3 six lines as an EC. The top 3 lines are pulling most of the weight for the most part and so it makes me wonder if there is a way to use the above info even if it is just to reduce a bit of the variance we may encounter.

 

As an example and the first 15 spins from today at the German Site.

1. 19=4 (1)
2. 8=2 (1)
3. 27=5 (1)
4. 12=2 (2)
5. 10=2 (3)
6. 34=6 (1)
7. 27=5 (2)
8. 13=3 (1)
9. 5=1 (2)
10. 33=6 (2)
11. 18=3 (2)
12. 11=2 (4)
13. 19=4 (1)
14. 33=6 (3)
15. 24=4 (2)

2 (7-12) = 4
4 (19-24) = 3
6 (31-36) = 3
3 (13-18) = 2
5 (25-30) = 2
1 (1-6) = 1

It doesn't stray too far away from the 4,4,3,2,1,1

 

If you have not seen it already, this little chart pretty much confirms what I am saying.



The numbers in the green boxes are the expected appearance time for the lines.

So for example, a line should come up for the 3rd time by spin 9 and then a second line should come out for the 3rd time by spin 13.

 

Playing the E.C's using this info might mean a bit of a stop / start game because of the 15 spin cycle but that wouldn't worry me one bit if it produced good results.

As an example, you could use a W/L registry and put a W if the current line is a repeat of the previous 3 and an L if it's different.

So using the 15 numbers from above.

1. 19=4 (1)
2. 8=2 (1)
3. 27=5 (1)
4. 12=2 (2) W
5. 10=2 (3) W
6. 34=6 (1) L
7. 27=5 (2) W
8. 13=3 (1) L
9. 5=1 (2) L
10. 33=6 (2) L
11. 18=3 (2) W
12. 11=2 (4) L
13. 19=4 (1) L
14. 33=6 (3) L
15. 24=4 (2) W

There are quite a concentration of L's towards the bottom and so looking at spin 13, the last 3 lines (including spin 13) are 3,2,4. Another L means it would produce either 1,5,6. You wouldn't play the 1 because it's only had one hit. The 5's had 2 hits and the 6 has had 2 hits. The two top numbers are the 4 and 2 but they have just come up in the last two spins. I suppose you could put half a unit on each as a cover bet to break even if either one of those two appear. Anyway, the 6 line appears on spin 14 and you would get paid out at even money.

That's one way and no doubt there are countless more.

 

Scrap this one because it's not worth the headache to convert things to an EC format. Better to use the repeater concept as originally intended.

Thanks