Baccarat Extreme Baccarat

Bactz not sure what there policy is but not wanting to take over posters thread

 

I can agree that we don't agree and you are free to have your opinion.

Have a nice day

 

Your reply got lost within my quote.

I really don't know how your applying it, doesn't matter. Running columns of 7, betting proceeding column won't match the prior, been there done that, folk can get very imaginative with how the manipulate columns and how they trigger off them. 1 in 127, yeah I get that, that only applies from the outset, these odds decrease after each lost bet, each bet is 50~50, 4 losses in a row doesn't make the nest bet a more likely winner cos you began with odds of 128/1. Having said that, I do play via columns, because I prefer playing this way, don't bet as much, each bet has a structure, reason, some fuzzy maths, my ABR is based on columns of 7.

7 column truth tables, which I've posted on this forum, will show, that it doesn't matter what you are doing, from the first bet through to the seventh bet will all resolve to 50%, yet if there are 128 different combinations of 7 hands, the likelihood of a match is 1/127, the less so for that 1 in 127 to occur back to back, wouldn't you agree? Welcome to the birth of ABR


I honestly can comment specifically on what you are doing, because I don't know exactly what it is you are doing, suffice to say, I suspect the expectation will be the same.

 

Junket King out of respect for your BAC experience i will say you are 100% wrong, think outside the box here betting for a series to repeat or not is simple math, you are talking about ordered combinations vs formulas applied two completely different types of math, i have read some of your posts and have gone through some of the same that you have stated, tried many all failed, that is why mechanical selections fail they really do not have the real math what is needed to win, when one can bet from non related results from any shoe one can win.

 

@Sputnik...

Would love for you to come back and take this topic back on track. I am interested to see/hear what findings you have come across for the Extreme Baccarat version

 

Okay BIG EZ I will explain ...
And you will see that the author of the Birthday Parado< is wrong in his assumptions.

First, you want to avoid situations where you get PBB and PBP as they cancel each other out.

PBB
PBP
PB - her you can not cover both

To get the trigger and use Cancelation Betting we avoid that situation to show.
And reduce the bets to three attempts.

Lets pick one pattern

PPB

Then we just bet P once no matter what pattern show we will win if they start with P
The reason and Cancelation Betting is to force to get two unique pattern to show.
Resulting in one single bet for the second attempts.

PPB
BPP

Next also cancellation betting
If we get P we bet PP and if we get B we bet BP

Assume we lose

PPB
BPP L
PBP L

The last bet force one unique pattern to show, other wise we win.

If PP we bet one more for PPB and if we get PPP we have three unique.
If PB we bet one more for PBP and if we get PBB we have three unique
If BP we bet one more for BPP and if we get BPB we have three unique

No repeats

PPB
BPP L
PBP L
PPP L

This is fictive cancellation betting and continues in the same way into the second phase where we place real bets.
Next, I will show to cover the cancel each other patterns in the second phace.

Cheers

 

p
b
p
p w
b
p
b
b w
p
p
b
b x
b
p
b
b w
b
b
p
b w
p
p
b
p w
b
p
b
b w
b
p
b
b w
p
b
b
b x
p
b
p
p x
p
p
p
b x

is this correct?

 

BIG EZ and ALL

Next phase there will be one single bet or two bets (depending on how the trigger unfold)
There is two things that can happen with the trigger.

You can get three of one group beginning with the same

PPB <
BPP
PBP <
PPP <

And you can get one trigger where you get two of each

PBB <
BBP
PBP <
PPB

This effect how to bet in the second and final phase.
Here is some examples:

2 Stand for Banker
1 Stand for Player

1 2 1
2 1 2 L
2 1 2 W
1 1 1 L
2 1 2 W
1 1 2 L
2 2 2 L
2 1 2 W
2 1 1 W
2 1 2 W
1 1 2 L
1 1 2 W
1 2 1 W
1 2 2 W
1 2 2 W
1 1 2 W
2 1 1 L
1 1 1 W
2 2 1 L
2 1 2 L
1 1 2 W
1 2 2 W
1 1 1 W
2 1 1 L
2 1 1 W
1 1 2 L
2 1 1 W
2 2 1 W
2 1 2 W
1 2 1 L
2 1 1 W
2 2 2 W
1 2 2 L
2 2 2 W
1 1 1 L
1 1 1 W
2 2 1 L
2 2 2 W <
1 2 2 L <
2 1 2 L <
2 1 1 L < TRIGGER

2 1 1 W

2 2 2
1 2 1 L
1 2 1 W <
2 1 2 L
1 1 2 L <
2 2 2 L TRIGGER

1 1 1 L
1 2 1 LW

A) The first trigger has one group with three of the same output 222 and 212 and 211
So when 21 show next we play on the formation 21 where 1 is the winning outcome.
That way we cover both 212 and 211 that cancel each other out.

B) Here we have two groups of each and in the second phase, we get three of one group 121 and 112 and 111.
So next we bet 11 as we have two groups cancel each other out 112 and 111.
We lose and get 21 and bet 212 and win.

Now you can ask a question and after that, i can explain the whole process.
Have to take it to step by step.

Cheers.

 

More illustration ...
Here are your random numbers:

2 2 2
1 2 1 L
2 1 2 L
1 1 2 L Trigger

1 2 1 W

1 2 1
2 2 1 L
2 1 2 L
1 1 2 L Trigger

2 1 2 W

1 1 2
2 1 2 L
2 1 2 W
1 2 2 L
1 2 2 W
1 2 1 W
2 2 1 L
1 1 2 L
2 2 2 W
2 1 2 W
1 1 1 L
2 1 2 W
1 2 2 L
1 2 2 W
1 1 2 W
1 1 2 W
1 2 1 W
1 1 1 W
1 2 2 W
2 2 1 L
2 2 2 W
2 1 1 W
1 1 1 L
1 1 2 W
2 2 2 L
2 1 2 L
2 1 2 W
1 2 1 L
2 2 2 L
2 2 2 W
1 2 2 L
1 2 1 W
2 1 2 L
1 1 2 L
2 2 2 L Trigger

1 1 2 W

 

Now it gets complex, but easy when you understand the process.
Let's say you get a scenario where four of each show with one group.

PBB <
BBP
PBP <
PPB <

PPP - Here we get four of each Player group PBB PBP PPB PPP and we would have bet for PB to show as we have PBB and PBP
The bet would cost two attempts to cover the PPP situation.
But later we only have to place one single bet.

Here we would bet before the next new outcome show for P and we cover all four.
If no win with continues the process with B groups where we only need to bet once.
So the whole process in this situation takes two bets.

Made a typo mistake at the reply where i describe one trigger with three groups of domination and two of each.
Below is the correct illustration:

Code:

You can get three of one group beginning with the same

PPB <
BPP
PBP <
PPP <

And you can get one trigger where you get two of each

PBB <
BBP
PBP <
BPB

 

Sputnik i always love everything that you post, your one of the few sincere people here, may i ask you again for a video, even thought i prefer betting on B

 

Thanks, AndyCasinoK - the problem is that I try to explain this method in the past.
Is complex when it comes to decision making.

If you understand how to get the trigger I can explain how to bet step by step instructions.

Cheers